claculate the no of atom of consitunts element in 5.85g of nacl
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Answered by
1
12.044 into 10to the power 22
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given mass= 5.85g
moles = given mass/ molar mass
= 5.85/23+35.5
=5.85/58.5
=0.1 mole
therefore atoms of Na in NaCl =0.1 × 6.022 × 10^23
atoms of Cl in NaCl is =0.1×6.022×10^23
hence total no of atoms in Nacl is :
2(6.022 ×10^22)
12.044 × 10^22
moles = given mass/ molar mass
= 5.85/23+35.5
=5.85/58.5
=0.1 mole
therefore atoms of Na in NaCl =0.1 × 6.022 × 10^23
atoms of Cl in NaCl is =0.1×6.022×10^23
hence total no of atoms in Nacl is :
2(6.022 ×10^22)
12.044 × 10^22
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