claculate the no of mole of nitrogen gas that contain 0.3011x1023
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bhai me abhi fifth class me hu sorry ye mujhe nahi pata.
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no. of moles of nitrogen gas=?
1mole =Avogadro number=6.023×10^23
no. of moles =no.of particles/6.023×10^23
no. of paticles=0.3011×10^23
no. of moles=(0.3011×10^23)/(6.023×10^23)
= 0.05mole
........... ............. ...........
hope this may help you.
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