claculate the number of moles and molecules in 1.4g of ethylene. what is the volume occupied and vapour density
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a) Mass of ethylene gas = 1.4 g.
Number of molecules is 0.05 mole ethylene = C2H2
= mass/molar mass = 1.4/28 = 0.5.
Number of molecules in 0.05 mole ethylene = 0.05 x 6 x 1023
= 3 x 1022 molecules.
1 mole of ethylene has volume at s.t.p. = 22.4 lit.
Volume occupied by 0.05 moles of ethylene gas at s.t.p.
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