Math, asked by sharmilam19bma025, 8 months ago

Clairaut' s Equation x dy/dx = y + log dy/dx * Clairaut' s Equation x dy/dx = y + log dy/dx *

Answers

Answered by AlluringNightingale
6

Answer :

y = cx - logc , where c is any arbitrary constant .

Note :

★ Clairaut's Equation : It is a differential equation of the form y = px + f(p) , where p = dy/dx .

★ The general solution of the Clairaut's Equation can be obtained by replacing p by c , where p = dy/dx and c is any arbitrary constant .

★ Thus , the general solution of the Clairaut's Equation y = px + f(p) is given as y = cx + f(c) , where c is any arbitrary constant .

Solution :

Here ,

The given Clairaut's Equation is ;

x(dy/dx) = y + log(dy/dx)

The given diffential equation can be rewritten as ;

=> xp = y + logp

=> y = xp - logp

=> y = xp + (-logp) , where p = dy/dx

Clearly ,

It is of the form y = px + f(p)

where f(p) = -logp

Thus ,

The general solution of the given Clairaut's Equation will be : y = cx - logc , where c is any arbitrary constant .

Hence ,

Required answer is : y = cx - logc where c is any arbitrary constant .

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