Science, asked by ashleykatebartolome4, 6 months ago

clasiffy the wheter the solution described is saturated,or unsaturated or supersaturated.

Solubility(grams solute per 100 ml solvent ) at 25 degrees Celsius.

*36
*80
*40
*50
*100

Solution at __
1. 36 grams in 100 mo solvent at 25 degrees Celsius

2.80 grams in 100 ml solvent at 25 degrees Celsius

3.80 grams in 100 ml solvent at 50 degrees Celsius

4. 100 grams in 200 ml solvent at 25 degrees Celsius grams

5. 150 grams in 100 ml solvent at 50 degrees Celsius


type of solution; pls answer it in correct ☺️
1._______
2._______
3._______
4._______
5._______

Answers

Answered by Tuktuki21
78

Answer:

Task 1: Producing a graph to represent solubility data

Potassium nitrate (KNO3) Sodium nitrate (NaNO3)

Temp. °C g / 100 g water g / 100 g water

60 108 124

70 136 134

80 168 148

Explanation:

the solubility of lead(II) nitrate and potassium nitrate is the same at about 50°C (approximately 80 g per 100 g water, where the solubility curves of these substances cross)

Answered by qwmagpies
1

36 grams in 100 ml solvent at 25 degrees Celsius the solution is saturated.

2.80 grams in 100 ml solvent at 25 degrees Celsius saturated.

3.80 grams in 100 ml solvent at 50 degrees Celsius this solution is unsaturated.

4. 100 grams in 200 ml solvent at 25 degrees Celsius this solution is unsaturated.

5. 150 grams in 100 ml solvent at 50 degrees Celsius this solution is supersaturated.

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