Question

Class 10
7x-15y=2
x+2y=3​

Answer 1

Given equations are

7x – 15y = 2 …(i)

x + 2y = 3 …(ii)

From eqn (ii), x = 3 – 2y …(iii)

On substituting x = 3 – 2y in eqn (i), we get

⇒ 7(3 – 2y) – 15y = 2

⇒ 21 – 14y – 15y = 2

⇒ 21 – 29y = 2

⇒ – 29y = – 19

y=19/29

put y

x=3-2 (19/29)

x=3-38/29

x=49/29

x=49/29

y=19/29

hope it help you

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Answer 2

Answer:

$7x - 15y = 2 \\ \: \implies7x = 2 + 15y \\ \implies \: x = \frac{2 + 15y}{7} \: \: \: \: \: \rightarrow(i) \\ \\ x + 2y = 3 \\ \implies\frac{2 + 15y}{7} + 2y = 3 \: (putting \: x = \frac{2 + 15y}{7} ) \\ \implies \frac{2 + 15y + 14y}{7} = 3 \\ \implies15y + 14y = 3 \times 7 - 2 \\ \implies29y = 21 - 2 \\ \implies \: y = \frac{19}{29} \\ \\ \\ \: \: substituting \: the \: value \: of \: y \: in \: equation \: (i) \\ 7x - 15 \times \frac{19}{29} = 2 \\ \implies7x - \frac{285}{29} = 2 \\ \implies7x = 2 + \frac{285}{29} \\ \implies7x = \frac{58 + 285}{29} \\ \\ \: \implies7x = \frac{343}{29 } \\ \\ \implies \: x = \frac{343}{203} \\ \\ \implies \: x = \frac{49}{29} \\ \\ \therefore \: x = \frac{49}{29} \\ \\ y = \frac{19}{29}$