Question

class 10 board must question ,please answer !!!!!!!!!!​

Answer 1

1+Sin²A= 3SinA Cos A.

Cos²A+Sin²A+Sin²A = 3SinA CosA [ 1 = Sin²+Cos A]

Cos²A+2Sin²A = 3SinA CosA....(1)

DIVIDE (1) BY COS²A we get,

1+2Tan²A = 3 TanA

1+2Tan²A - 3 TanA = 0

(2TanA-1) ( TanA-1) = 0

2TanA -1 = 0. TanA -1= 0

2TanA = 1. TanA =1

TanA = 1/2. TanA = 1

Hope it helps you.

Answer 2

hope it helps

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