Question

class 10 cbse ........​

Answer 1

Answer:

x=0 or 4

Step-by-step explanation:

Answer 2

Answer:

$\frac{1}{(x + 1)(x - 2)} + \frac{1}{(x - 2)(x - 3)} = \frac{2}{3} \\ \frac{(x - 3) + (x + 1)}{(x + 1)(x - 2)(x - 3) } \: = \frac{2}{3} \\ 3(x - 3 + x + 1) = 2(x + 1)(x - 2)(x - 3) \: \\ 3(2x - 2) = 2(x + 1)(x - 2)(x - 3) \\ 6(x - 1) = 2(x + 1)(x - 2)(x - 3) \\ 3(x - 1) = (x + 1)(x - 2)(x - 3)$

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$3(x - 1) = (x + 1) \\ 3x - 3 = x + 1 \\ 3x - x = 1 + 3 \\ 2x = 4 \\ x = 2$

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$3(x - 1) = (x - 2) \\ 3x - 3 = x - 2 \\ 3x - x = 3 - 2 \\ 2x = 1 \\ x = \frac{1}{2}$

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$3(x - 1) = (x - 3) \\ 3x - 3 = x - 3 \\ 3x - x = 3 - 3 \\ 2x = 0 \\ x = 0$

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