Question

Class 10 (chapter 4)
RD
A two digit number is such that the product of digits is 12.
When 36 is added to the number the digits interchange their places formulate the quadratic equation whose route is digit of a number.​

Answer 1

let number = 10x + y

according to question,

xy = 12 --------(1)

again,

10x + y + 36 = 10y + x

9x - 9y = 36

x - y = 4

x = 4 + y

put this in equation (1)

y( y + 4) = 12

y² + 4y -12= 0

hence, quadratic equation ,

is y² + 4y -12 = 0

solve this y = 6, but y ≠ -2

then , x = 2

so,number= 10×2 + 6 =26

Answer 2

$quadratic \: equation \: is \: {x}^{2} + 4x - 12 = 0$