Question

class 10 chapter 6 Maths question​

Answer 1

15cm

Step-by-step explanation:

$in \: triangles \: aoq \: and \: bop \\ we \: have \\ < oaq = < obp(each \: equal \: to \: {90}^{0} ) \\ < aoq = < bop \\ (vertically \: opposite \: angles)$

Therefore, by AA- criterion of similarity, we obtain

tri AOQ ~ tri BOP

$\frac{ao}{bo} = \frac{oq}{op} = \frac{aq}{bp} \\ \frac{ao}{bo} = \frac{aq}{bp} \\ \frac{10}{6} = \frac{aq}{9} \\ aq = \frac{10 \times 9}{6} = 15cm$

Hope it helps you.

Answer 2

Answer:

Hope it help you......