Question

class 10 circle question​

Answer 1

DIAGONAL of square is equal to diameter = 16cm.

By Pythagoras a (side of square) = 8✓2cm

Area =

${a}^{2}$

${(8 \sqrt{2)} }^{2}$

= 128 sq.cm

Answer 2

Diagonal of the square = 2r= 2×8 cm= 16 cm.

Thus, side of the square=16/root2(Use Pythagoras theorem)

= 8root2

area of square= (8root2)^2

=128cm^2(ans)(option B)

Hope this helps you mate ..

If yes please mark me as brainliest.....