Question

class 10 Find the value of k such that the quadratic polynomial x2 - (k + 6)x - 2(2k + 1 ) has sum of the zeroes is half of their product .

Answer 1

Answer:

Let the roots be α,β

For a quadratic equation ax

2

+bx+c=0

Sum of roots α+β=k+6⋯(1)

Product of roots αβ=4k−2⋯(2)

According to question,

α+β=

2

αβ

From (1),(2)

⟹k+6=2k−1

⟹k=7

Step-by-step explanation:

please give thank and please mark as brilliant