Question

class 10 icse,maths​

Answer 1

Area of the square piece of land

= (56)² = 3136m²

Area of the 2 semicircular portions of land

$= 2( \frac{1}{2} \times \pi {r}^{2} ) \\ = \pi {r}^{2} \\ = \pi {28}^{2} \\ = 784\pi \\ = 784 \times 3.14 = 2461.76 {m}^{?}$

Hence, area of uncovered area

= 3136 - 2461.76

= 674.24m²