Math, asked by Pratishtha2003, 1 year ago

Class 10 math..guyz please help me 2 din baad board h​

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SEHANSHAH: hlo
SEHANSHAH: pratishtha

Answers

Answered by Anonymous
0

Answer: 5 minutes

Step-by-step explanation:

Thief runs 100 m in 1 minute.

When the policeman started the thief had already covered 100 m.

Every succeeding minute, the policeman increases his speed by 10m/min.

In 1 minute: relative speed = 10 m/min

So, in every minute the police travels 10 m more than the previous distance.

2 minutes, thief = 200 m

1st minute of police = 100 m

From here, in every minute the police covers 10 m more than the previous distance covered by himself.

Next minute: thief = 300m , police = 210 m

Next minute: thief = 400m , police = 330 m

Next minute: thief = 500m , police = 460 m

Next minute: thief = 600 m, police = 600 m

The policeman travelled 5 minutes.


Anonymous: Oh! 10 m more in every minute...
SEHANSHAH: hlo pratishtha
Anonymous: I've edited it. See whether its correct. Thanks for pointing the misinterpretation.
SEHANSHAH: no
SEHANSHAH: It's wrong
Pratishtha2003: See I dont think its correct but sorry to say
SEHANSHAH: answer is 5 min .
Pratishtha2003: yep
Anonymous: Sorry for the mistake.
SEHANSHAH: not big issue
Answered by SEHANSHAH
1

Hlo Pratishtha

I tell u tomorrow also but cannot give explanation because of one spam answer...........

HERE IS UR ANSWER

Let the policeman catch the thief in n minutes.

Given that uniform speed of the thief = 100m/min.

Given that After 1 minute a policeman runs to catch him at the speed of 100 in first minutes.

(n + 1) minutes = 100(n + 1) minutes.

Given that speed of policeman increase by 10m/min.

The speed of police in 1 minute = 100m/min.

The speed of police in 2 minutes = 110m/min.

The speed of police in 3 minutes = 120m/min.

The speed of police in 4 minutes = 130m/min.

Hence 100,110,120,130 are in AP.

Let a be the first term and d be the common difference.

a = 100,d = 110 - 100 = 10.

We know that sum of n terms of an ap = n/2(2a + (n - 1) * d)

= n/2(2(100) + (n - 1) * 10) ------ (1)

The distance traveled by the thief = Distance traveled by the police

100(n + 1) = n/2(2 * 100+ (n - 1) * 10)

100n + 100 = n/2(200 + 10n - 10)

200n + 200 = 10n^2 + 190n

10n^2 + 190n - 200 = 200n

10n^2 - 10n - 200 = 0

n^2 - n - 20 = 0

n^2 -5n + 4n - 20 = 0

n(n - 5) + 4(n - 5) = 0

(n -5)(n + 4) = 0

n = 5 (or) n = -4.

n cannot be negative.

Therefore the time is taken by the policeman to catch the thief = 5minutes.

I HOPE IT HELPS YOU

PLZ MARK IT AS A BRAINLIEST

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