Question

Class 10

Mathematics

Chapter 8 - Introduction to Trigonometry

Formulas Needed

Quality Answer Needed .​

Answer 1

Answer:

Hey Here is formulae of Trigonometry chapter

Step-by-step explanation:

Hope it's helpful for you

Answer 2

Answer:

Step-by-step explanation:

The formulas required for Trigonometry are :-

$\sf{ sin \theta = \dfrac{Height}{Hypotenuse}}$

$\sf{ cos \theta = \dfrac{Base}{Hypotenuse}}$

$\sf{ tan \theta = \dfrac{Height}{Base}}$

$\sf{ cot \theta = \dfrac{Base}{Height}}$

$\sf{ sec \theta = \dfrac{Hypotenuse}{Base}}$

$\sf{ cosec \theta = \dfrac{Hypotenuse}{Height}}$

From this, we can derive relations as:-

$\sf{ sin \theta = \dfrac{1}{Cosec \theta}}$

$\sf{ cos \theta = \dfrac{1}{Sec \theta}}$

$\sf{ Tan \theta = \dfrac{1}{ Cot \theta}}$

$\sf{ cot \theta = \dfrac{1}{tan \theta}}$

$\sf{ sec \theta = \dfrac{1}{cos \theta}}$

$\sf{ cosec \theta = \dfrac{1}{Sin \theta}}$

Squaring Identities :-

$\sf{ sin^2 \theta = 1 - cos^2 \theta}$

$\sf{ tan^2 \theta = sec^2 \theta - 1}$

$\sf{ cot^2 \theta = cosec^2 \theta - 1}$

External formulas:-

$\sf{ tan \theta = \dfrac{sin \theta}{cos \theta}}$

$\sf{ cot \theta = \dfrac{cos \theta}{sin \theta}}$