Question

CLASS 10 MATHS
ANSWER PLEASE

Answer 1

Step-by-step explanation:

hence option A) is the answer

Answer 2

ANSWER = (A) a = 13/7 , b = 9/7

$\huge\sf\underline{\underline{ Question}}$

$\sf\pink{\frac{3+2\sqrt{2}}{3- \sqrt{2} } = a + b√2 . Find \: a \: and \: b }$

$\huge\sf\underline{\underline{Answer}}$

$\frac{3 + 2 \sqrt{2} }{3 - \sqrt{2} } = \frac{(3 + 2 \sqrt{2}) \times (3 + \sqrt{2} )}{(3 - \sqrt{2}) \times (3 + \sqrt{2}) }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{9 + 3 \sqrt{2} + 6 \sqrt{2} + 4}{ {3}^{2} - { \sqrt{2} }^{2} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{13 + 9 \sqrt{2} }{9 - 2 }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{13 + 9 \sqrt{2} }{7}$

$a \: = \frac{13}{7}$

$b \: = \frac{9}{7}$