Question

Class 10 maths frustum of cone

Answer 1

volume:1/3πh(r1^2+r2^2+r1r2)

Answer 2

it is The cut part of a cone
ex- glass or buckets are the frustum
it's volumn is 1/3π(R^2+r^2+Rr)h
here R-radius of big circle
r=radius of Small circle
curve surface
=π(R+r)l

l^2=h^2+(R-r)^2
l=√h^2+(R-r)^2

total surface of frustum

curve surface + total area of both circle
π(R+r)l + πr^2 + πR^2
π(R+r)l+π(R^2+r^2)
I(R+r)(l+R+r)