Question

CLASS 10 MATHS..pls tell if you know​

Answer 1

Step-by-step explanation:

Given:If $\alpha$,$\beta$ are zeroes of

$f(x) = p {x}^{2} - 2x + 3p$

and

$\alpha+\beta=\alpha\beta$.

To find: Value of p.

Solution:

We know that their is a relation between zeroes and coefficients of quadratic polynomial.

$\alpha + \beta = \frac{ - b}{a} \\ \\ \alpha \beta = \frac{c}{a}$

if ax²+bx+c is the quadratic polynomial.

Here,

a=p

b=-2

c=3p

put the values in the given condition

$\alpha + \beta = \frac{2}{p} \\ \\ \alpha \beta = \frac{3p}{p}$

Equate both

$\frac{2}{p} = \frac{3p}{p} \\ \\ or \\ \\ \frac{2}{p} = 3 \\ \\ p = \frac{2}{3}$

Final answer:

Value of p is 2/3.

Hope it helps you.

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