Question

class 10 physics
find current across 4 ohm​

Answer 1

Answer :

Three identical resistors are connected with a bettery of 2V as shown in the figure.

We have to find current flow in 4Ω resistor$.$

As per ohm's law, Current flow through resistor is directly proportional to the applied potential difference.

We know that, Current flow through each resister remains same in series connection.

◈ First we have to find equivalent resistance of circuit :

➝ Req = R¹R²/(R¹+R²) + R³

➝ Req = (8×8)/(8+8) + 4

➝ Req = 64/16 + 4

➝ Req = 4 + 4

➝ Req = 8Ω

◈ Current flow in circuit :

➝ V = I × Req

➝ 2 = I × 8

➝ I = 2/8

➝ I = 0.25A

፨ Current flow through 4Ω resistor = 0.25A

☃ God_Bless :)

Answer 2

Given ,

• The parrallel combination of 8 ohm and 8 ohm is in series with 4 ohm

• Potential difference (v) = 2 v

Thus , the equivalent resistance of 8 ohm and 8 ohm will be

1/R' = 1/8 + 1/8

1/R' = 2/8

R' = 4 ohm ,

Now , R' form a series combination with 4 ohm

Thus , the total resistance of the circuit

R = 4 + 4 = 8 ohm

$\therefore$ The current through 4 ohm resistor will be

I = 2/8

I = 0.25 amp

Therefore ,

The current through 4 ohm resistor is 0.25 ohm