Class 10 real numbers Q4
Attachments:
Answers
Answered by
0
hey mate here is your answer
let the HCF be x
in order to make 615 and 963 completely divisible by x,we need to deduct the remainder 6 from both the cases
609=3*3*29
957 =3*11*29
x=3*29=87
therefore, largest number which divides 615 & 963 leaving remainder 6 in each case is 87
hope u r happy with this answer
mark it as brainliest if u r happy with this answer
haply new year mate
let the HCF be x
in order to make 615 and 963 completely divisible by x,we need to deduct the remainder 6 from both the cases
609=3*3*29
957 =3*11*29
x=3*29=87
therefore, largest number which divides 615 & 963 leaving remainder 6 in each case is 87
hope u r happy with this answer
mark it as brainliest if u r happy with this answer
haply new year mate
Similar questions