Class 10 solve this question
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Jahnavidax:
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So as A+B+C=180°
and C=2(A+B)
A+B+2(A+B)=180°
3(A+B)=180°
A+B=60°
Therefore, C=120°
As C=3B
120°=3B
40°=B
And at last, 120°+40°+A=180°
A=20°.
Therefore A=20°, B=40° and C=120°.
Hope you were helped. Cheers mate. :)
and C=2(A+B)
A+B+2(A+B)=180°
3(A+B)=180°
A+B=60°
Therefore, C=120°
As C=3B
120°=3B
40°=B
And at last, 120°+40°+A=180°
A=20°.
Therefore A=20°, B=40° and C=120°.
Hope you were helped. Cheers mate. :)
Answered by
0
Answer:
o as A+B+C=180°
and C=2(A+B)
A+B+2(A+B)=180°
3(A+B)=180°
A+B=60°
Therefore, C=120°
As C=3B
120°=3B
40°=B
And at last, 120°+40°+A=180°
A=20°.
Therefore A=20°, B=40° and C=120°.
Hope you were helped. Cheers mate. :)
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