Question

class 10 standard maths​

Answer 1

Answer:

question error, it is under root b⁴+4A²

Answer 2

Step-by-step explanation:

ABC be a right angled triangle

right angled at B

let BC = b

area of right angled triangle. A = 1/2 × b × h

h = 2A/b

AC is hypotenuse

(AC)2 = √b2+4A2/ b2

= 1/b √b2 + 4A2

area of right angled triangle containing hypotenuse

A = 1/2 × 1/b √b2+ 4A2 × h

2Ab = √ b2 + 4A2 × h

h = 2Ab/√b2+4A2