Question

class 10 substitution method one example in easy way

Answer 1

Step-by-step explanation:

In this way, we can find out the value of the unknowns x and y using the substitution method. Example 2: Solve the pair of linear equations: 4x + 6y = 10 and 2x – 3y = 8 using Substitution method.

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Answer 2

Answer:

ok

let's take 4x+2y=7 and 7x-8y=9

4x+2y=7 ....(i)

and

7x-8y=9 ......(ii)

now,

from (i) let's substitute the value of x,

$x = \frac{7 - 2y}{4}$

let the above equation be equation (iii)

Now,

put the value of x in (ii) from (iii)

we get,

$7( \: \frac{7 - 2y}{4} ) - 8y = 9$

now,

let's solve this.....

$\frac{49 - 14y}{4} - 8y = 9$

now let's take the LCM of the LHS(left hand side)

$49 - 14y - 32y = 9 \times 4$

$49 - 46y = 36$

$- 46y = 36 - 49$

$- 46y = - 13$

$y = \frac{ - 13}{ - 46}$

$y = \frac{13}{46}$

Now, we got the value of 'y'

let's put the value of y in iii to get our x.

$x = \frac{7 - 2( \frac{13}{46)} }{4}$

x = 678/100

Step-by-step explanation:

hey mate, hope this helps....

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