Question

class 10 th maths question ​

Answer 1

Answer:

2cosecA

Step-by-step explanation:

tenA/1+secA - tenA/1-secA

tenA(1/1+secA - 1/1-secA)

tenA (1-secA-1-secA)/(1-sec^2A)

tenA(-2secA)/-ten^2A

tenA(2secA/ten^2A)

tenA*2secA/ten^2A

(2*1/cosA)*(cosA/sinA)

2/sinA

2cosecA

Answer 2

Hope you will mark me as brainliest.

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