class 10 th maths question
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Answer:
2cosecA
Step-by-step explanation:
tenA/1+secA - tenA/1-secA
tenA(1/1+secA - 1/1-secA)
tenA (1-secA-1-secA)/(1-sec^2A)
tenA(-2secA)/-ten^2A
tenA(2secA/ten^2A)
tenA*2secA/ten^2A
(2*1/cosA)*(cosA/sinA)
2/sinA
2cosecA
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