Question

Class 10
Topic- Circles

please solve the attachment ​

Answer 1

Answer:

i tool bio in 11th that y if forgot the properties so i can't ansr the question.

Answer 2

Answer:

since pq is the diameter

angle PRQ=90° (angle in a semi circle)

therefore,

angle RQS= 30+90 ( exterior angle property)

In triangleRQS

angle QRS= 180-120-30

=30°

Since both angle of traingle are equal

RQ=RS(base angle of isoscles triangle are equal)

hence proved

hope this helps

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