class 10 - Triangles
Pls help me friends.....
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here's your answer dude.
let one side ve x and another be y
and let traingle's name be ABC and b be 90 degree
perimeter = sum of all sides
60=x+y+25
x+y=60-25
y=35-x....(1)
in right angled traingle
AC^(square)=x^(square)+y^(square)
25^(square)=x^(square)+(35-x)^(square)
625=x^(square)-1225-70x+x^(square)
2x^(square)-70x-600=0
2(x^(square)-35x-300)=0
2(x-15)(x-20)
x=15or x=20
jope it helpz plz mark as brainliest
let one side ve x and another be y
and let traingle's name be ABC and b be 90 degree
perimeter = sum of all sides
60=x+y+25
x+y=60-25
y=35-x....(1)
in right angled traingle
AC^(square)=x^(square)+y^(square)
25^(square)=x^(square)+(35-x)^(square)
625=x^(square)-1225-70x+x^(square)
2x^(square)-70x-600=0
2(x^(square)-35x-300)=0
2(x-15)(x-20)
x=15or x=20
jope it helpz plz mark as brainliest
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