Question

Class 10 trigonometry

Answer 1

Answer:

${ \cot}^{2} x - \frac{1}{ { \sin }^{2}x } \\ = \frac{ { \cos}^{2} x}{ { \sin }^{2} x} - \frac{1}{ { \sin}^{2} x} \\ \\ = \frac{ { \cos}^{2} x - 1}{ { \sin }^{2} x} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ( { \sin}^{2} x + { \cos }^{2}x = 1) \\ \\ = - \frac{ { \sin}^{2}x }{ { \sin}^{2} x} \\ \\ \\ - 1$

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Answer 2

Answer:

${ \cot }^{2} = { \cos }^{2} \div { \sin }^{2} \\ therefore \: \: \: { \cos }^{2} - 1 \div { \sin }^{2} \\ = - { \sin }^{2} \div { \sin}^{2} \\ = - 1$

-1 is ur answer ......

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