Question

CLASS 10
TRIGONOMETRY


PLS ANSWER THIS QUESTION
by hand written ​

Answer 1

Answer:

I attached a picture for step by step explanation

Answer 2

$start \:\:solving \:\:from \:\:the\:\: left$

Step-by-step explanation:

$LHS= \frac{sin \theta + cos \theta}{sin \theta - cos \theta} + \frac{sin \theta - cos \theta}{sin \theta + cos \theta} \\ = \frac{(sin \theta + cos \theta) ^{2} + (sin \theta - cos \theta)^{2} }{(sin \theta - cos \theta) (sin \theta + cos \theta)} \\ = \frac{sin^{2} \theta + cos^{2} \theta + 2.sin \theta.cos \theta + sin^{2} \theta + cos^{2}\theta -2.sin \theta.cos \theta }{sin^{2} \theta - cos^{2} \theta} \\ = \frac{1 + 1}{sin^{2} \theta - cos^{2} \theta} \\ = \frac{2}{sin^{2} \theta - cos^{2} \theta} \\ = \frac{ \frac{2}{cos^{2} \theta} }{ \frac{sin^{2} \theta - cos^{2} \theta}{cos ^{2} \theta } } \\ = \frac{2sec^{2} }{ \frac{sin^{2} \theta }{cos^{2} \theta} - \frac{cos^{2} \theta}{cos^{2} \theta} } \\ = \frac{2sec^{2} \theta}{tan^{2} \theta - 1} = RHS$