Class 10 worksheets 7 solve all questions solved fast plz
Answers
Answer:
Explanation:
एक प्रेम कविता हमेशा लंबी और फूलों वाली नहीं होगी। कभी-कभी आपको जो कहने की ज़रूरत होती है वह बहुत कम हो सकती है। वास्तव में यह तथ्य हो सकता है कि कविता छोटी है जो इसे विशेष बनाती है। इसकी कम लंबाई यह दिखा सकती है कि आपने हर शब्द को गिनने के लिए समय और मेहनत लगाई है। आपने ध्यान से हर शब्द का चुनाव किया। हर शब्द की पसंद के पीछे एक कारण होता है। एक छोटी कविता रोमांस का अंतिम कार्य हो सकती है जब उसे वह समय और प्रयास दिया जाता है जिसके वह हकदार है।
Answer:
carboxyl group is removed from pyruvate, releasing a molecule of carbon dioxide into the surrounding medium. (Note: carbon dioxide is one carbon attached to two oxygen atoms and is one of the major end products of cellular respiration. ) The result of this step is a two-carbon hydroxyethyl group bound to the enzyme pyruvate dehydrogenase; the lost carbon dioxide is the first of the six carbons from the original glucose molecule to be removed. This step proceeds twice for every molecule of glucose metabolized (remember: there are two pyruvate molecules produced at the end of glycolysis); thus, two of the six carbons will have been removed at the end of both of these steps.
Step 2. The hydroxyethyl group is oxidized to an acetyl group, and the electrons are picked up by NAD+, forming NADH (the reduced form of NAD+). The high- energy electrons from NADH will be used later by the cell to generate ATP for energy.
Step 3. The enzyme-bound acetyl group is transferred to CoA, producing a molecule of acetyl CoA. This molecule of acetyl CoA is then further converted to be used in the next pathway of metabolism, the citric acid cycle.
Key Points
In the conversion of pyruvate to acetyl CoA, each pyruvate molecule loses one carbon atom with the release of carbon dioxide.
During the breakdown of pyruvate, electrons are transferred to NAD+ to produce NADH, which will be used by the cell to produce ATP.
In the final step of the breakdown of pyruvate, an acetyl group is transferred to CoeReflection is the change in direction of a wavefront at an interface between two different media so that the wavefrontT+mg=mv^2/r. Change the subject of the formula to the letter given against ...