class 10th
draw graph of the following and find zeros
p(x)= x2-x-12
p(x)=x2-6x+9
its urgent
plsssssss
Answers
Answered by
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Heya !!!
This is your answer.
Given :-
p (x) = x² -x - 12.
We have to find two numbers a and b such that a+b = -1 and ab = -12.
By looking at Prime factors of 12,
12 = 2×2×3.
We get a and b as 2×2=4 and 3.
So.....
x² -x + 12 = 0
x² -4x + 3x - 12 = 0.
x(x-4) + 3 (x-4) = 0.
(x+3)(x-4) = 0.
Comparing with 0,
x+3 = 0 and x - 4 = 0.
x = -3 or x = 4
Hence, the zeroes of the polynomial is -3 and 4.
Next......
p(x)=x² -6x+9
We have to find two numbers a and b such that a+b = -6 and ab = 9.
By looking at Prime factors of 9,
9 = 3×3.
We get a and b as -3 and -3.
So.....
x² -6x +9 = 0
x² -3x - 3x + 9 = 0.
x (x-3) - 3 (x -3) = 0
(x -3) (x -3) = 0.
Comparing with 0,
(x - 3= 0). or ( x-3 = 0)
x = 3 or x = 3
Hence, the zeroes of the polynomial are 3 and 3.
Hope it helps
This is your answer.
Given :-
p (x) = x² -x - 12.
We have to find two numbers a and b such that a+b = -1 and ab = -12.
By looking at Prime factors of 12,
12 = 2×2×3.
We get a and b as 2×2=4 and 3.
So.....
x² -x + 12 = 0
x² -4x + 3x - 12 = 0.
x(x-4) + 3 (x-4) = 0.
(x+3)(x-4) = 0.
Comparing with 0,
x+3 = 0 and x - 4 = 0.
x = -3 or x = 4
Hence, the zeroes of the polynomial is -3 and 4.
Next......
p(x)=x² -6x+9
We have to find two numbers a and b such that a+b = -6 and ab = 9.
By looking at Prime factors of 9,
9 = 3×3.
We get a and b as -3 and -3.
So.....
x² -6x +9 = 0
x² -3x - 3x + 9 = 0.
x (x-3) - 3 (x -3) = 0
(x -3) (x -3) = 0.
Comparing with 0,
(x - 3= 0). or ( x-3 = 0)
x = 3 or x = 3
Hence, the zeroes of the polynomial are 3 and 3.
Hope it helps
Anonymous:
thank u bro
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