Question

class 10th

draw graph of the following and find zeros
p(x)= x2-x-12
p(x)=x2-6x+9




its urgent
plsssssss

Answer 1

Heya !!!

This is your answer.

Given :-
p (x) = x² -x - 12.

We have to find two numbers a and b such that a+b = -1 and ab = -12.

By looking at Prime factors of 12,
12 = 2×2×3.

We get a and b as 2×2=4 and 3.

So.....
x² -x + 12 = 0
x² -4x + 3x - 12 = 0.
x(x-4) + 3 (x-4) = 0.
(x+3)(x-4) = 0.
Comparing with 0,
x+3 = 0 and x - 4 = 0.
x = -3 or x = 4

Hence, the zeroes of the polynomial is -3 and 4.

Next......

p(x)=x² -6x+9
We have to find two numbers a and b such that a+b = -6 and ab = 9.

By looking at Prime factors of 9,
9 = 3×3.

We get a and b as -3 and -3.

So.....
x² -6x +9 = 0
x² -3x - 3x + 9 = 0.
x (x-3) - 3 (x -3) = 0
(x -3) (x -3) = 0.

Comparing with 0,
(x - 3= 0). or ( x-3 = 0)
x = 3 or x = 3
Hence, the zeroes of the polynomial are 3 and 3.

Hope it helps