Question

Class 10th Ex. 4.1

(1): (x+1)square=2(x-3)

Solution:
${x}^{2} + {1}^{2} + 2(x)(1) = 2(x - 3) \\ {x}^{2} + 1 + 2x = 2x - 6 \\ {x}^{2} + 1 - 6 \\ x2 - 5 \\ thus \: this \: is \: a \: quardratic \: eqution$
First we have to use formula (x+1) whole square. And multiply 2 with (x-3) and solve it.
Hope you understand it
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Answer 1

$answer \: \: is \: \: {x}^{2} - 7 = 0$