Question

class 10th ex 8.1 example 1​

Answer 1

Solution:

In a given triangle ABC, right angled at B=B = g0* Given: AB - 24 cm and BC-7 cm

According to the Pythagoras Theorem,

Page: 181

in a right-angled triangle, the squares of the hypotenuse side is equal to the sum of the squares of the

other two sides By applying Pythagoras theorem, we get

${ac}^{2} = {ab}^{2} + {bc}^{2}$

${ac}^{2} = {24}^{2} + {7}^{2}$

${ac}^{2} = (576 + 49)$

${ac}^{2} = 625 {cm}^{2}$

$ac = \sqrt{625} = 25$

$therefore \: ac = 25cm$

) To find Sin (A), Cos (A)

We know that sine (or) Sin function is the equal to the ratio of length of the opposite side to the hypotenuse side. So it becomes Sin (A) = Opposite side / Hypotenuse = BC/AC=1/25

Cusine or Cos function is equal to the ratio of the length of the adjacent side to the hypotenuse side

and it becomes Cos IA) = Adjacent side/Hypotenuse = AB/AC = 24/2s

(in To find Sin (C), Cos 1C)

Sin (C) = AB/AC= 24/25 Cos IC) = BC/AC = 7/25

HOPE IT'S HELPS YOU ❣️

HAVE A GREAT DAY AHEAD ❣️

Answer 2

Answer:

HERE IS YOUR ANSWER BUDDY.