Question

Class 10th mathematics, question!

please provide me some reason if you know the answer!​

Answer 1

$\Huge\underline\mathtt{\red{Answer:-}}$

$\longrightarrow$ 1) $\Large\frac{PZ}{XZ}$

Step-by-step explanation:

$\Large\underline\mathtt{\red{Question:-}}$

$\implies$ Find:- $\frac{ZX}{ZY}$ from the figure in the attachment.

$\Large\underline\mathtt{\blue{Hint:-}}$

• We will use the concept of similarity here.

$\Large\underline\mathtt{\purple{Solution:-}}$

In ∆ YXZ and ∆ PXZ;

$\angle$ YZX = $\angle$ PZX (common)

$\angle$ YXZ = $\angle$ XPZ (given)

$\therefore$ ∆ YXZ ~ ∆ PXZ (by AA)

$\implies$ $\frac{PZ}{XZ}$ = $\frac{ZX}{ZY}$ = $\frac{YZ}{XZ}$

(As corresponding sides of similar triangles are in proportion)

Hence, option 1 is correct.

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$\tiny\mathfrak{\red{@MissTranquil}}$