Class 10th maths
A box contains 90 discs which are numbered from 1 to 90 . if one disc is selected at random from the box ,find the probability that it bears (1) a two-digit number.(2) a perfect square number. (3) a number divisible by 5.
suppose you drop a die at random on the rectangular region shown in figure. what is the probability that it will land inside the circle with diameter 1 m
its really urgent guyss
Ankeeru:
which one is correct answer
Answers
Answered by
8
1)Favourable outcomes=81
Total no. of outcome =90
Probability =81/90=9/10
2) Favourable outcome=9
Total no. of outcomes =9/90=1/10
3)Favourable outcomes =18
Total no. of outcomes=90
Probability =18/90=1/5
As you have not uploaded any picture so i am not able to answer your next question
hope it helps
plz mark brainliest
Total no. of outcome =90
Probability =81/90=9/10
2) Favourable outcome=9
Total no. of outcomes =9/90=1/10
3)Favourable outcomes =18
Total no. of outcomes=90
Probability =18/90=1/5
As you have not uploaded any picture so i am not able to answer your next question
hope it helps
plz mark brainliest
Answered by
4
1)Two digit number outcomes= 81
total discs= 90
probability=81/90=9/10
2)perfect square outcomes=9
total discs=90
probability=9/90=.1/10
3)number divisible by 5 outcomes=18
total discs=90
probability=18/90=1/5
1)two digits number=10to90
2) perfect square=1to81
3)number divisible by 5=5,10.............90
total discs= 90
probability=81/90=9/10
2)perfect square outcomes=9
total discs=90
probability=9/90=.1/10
3)number divisible by 5 outcomes=18
total discs=90
probability=18/90=1/5
1)two digits number=10to90
2) perfect square=1to81
3)number divisible by 5=5,10.............90
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