Class 10th me quadratic equations ka situational problem(word problem) aaegi kya??
Answers
Answered by
1
Ha yes it will come maybe
Answered by
3
yes officious Quadratic Word Problems are important
THIS TYPE OF QUESTIONS ARE COMING IN EXAM
. Determine two consecutive negative even integers whose product is 24?
SolutionLet n and n-2 be the two consecutive negative even integers
then
n
(
n
−
2
)
=
24
n
2
−
2
n
−
24
=
0
or
(
n
−
6
)
(
n
+
4
)
=
0
n=6 or -4
Since we want the negative integers only, n=-4
other number =n-2= -4-2 = -6
So numbers are (-6,-4)
Question 3
A rectangle has a length that is 2 less than 3 times the width. If the area of this rectangle is 16, find the dimensions and the perimeter.
SolutionLet x= the length of the rectangle and y= its width
As per the question
x
=
y
−
2
Given ,The area of this rectangle is 16
Now
A
r
e
a
=
x
y
=
16
or
(
3
y
−
2
)
y
=
16
3
y
2
−
2
y
−
16
=
0
Factoring
(
3
y
−
8
)
(
y
+
2
)
=
0
y = 8/3 and -2
Since we can't have a negative width, y= 8/3
Now x=3y-2 = 6
Perimeter = 2x + 2y = 12 + 16/3 = 64/3
Similar questions