class 10th ncert book maths chapter 13 exercise 13.2 questions 2
plz give me ans. fast
Answers
Answered by
2
Answer:
Height (h1) of each conical part = 2 cm
Height (h2) of cylindrical part = 12 − 2 × Height of conical part
= 12 − 2 ×2 = 8 cm
Radius (r) of cylindrical part = Radius of conical part = 3/2 cm
Volume of air present in the model = Volume of cylinder + 2 × Volume of
cone
Answered by
4
Step-by-step explanation:
Height of cylinder h1 = 12 - 2 - 2
= 12 - 4 => 8
Volume of air contained in the solid = volume of cylinder + 2 × volume of cone
= π r² h1 + 2 × 1/3 π r² h2
= π r² [h1 + 2/3 × h2]
= 22/7 ×3/2 × 3/2 [8 + 2/3 × 2]
= 99/14 [8 + 4/3]
= 99/14 × 28/3
= 66 cm³
HOPE IT HELPS YOU BUDDY.....
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