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Area of triangle = (1/2)xbasexheight
Area (ΔABC) = (1/2)x BCxAB
Area (ΔADC) = (1/2)x ADxAB
Therefore,
Area (ΔABC) BC
——————- = —- = 4/8 = 1/2
Area (ΔADC) AD
Area (ΔABC) = (1/2)x BCxAB
Area (ΔADC) = (1/2)x ADxAB
Therefore,
Area (ΔABC) BC
——————- = —- = 4/8 = 1/2
Area (ΔADC) AD
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