Question

class 11 chemistry question​

Answer 1

ANSWER - mvr = nh/2 pie               -------(2)                             given

by de brogile wavelength   i.e

Lembda = h/mv

Lembda [mv] = h             -----(1)

from equation 1 & 2

mvr=n lembda mv

cross mv and last mv

we get:

2pier=nlembda

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Answer 2

Answer: The expression for the angular momentum is mvr=  nh /2π

       , or 2πr=  nh /mv   ......(i)

The wavelength is given by the De Broglie's equation.

λ=  h/mv  .....(ii)

From (i) and (ii), we have

2πr=nλ

Hence, the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie's wavelength associated with the electron revolving around the orbit.

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Good question by the way!!

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