Physics, asked by rajlanjhi9712, 1 year ago

class 11-kinematics-motion in a straight line-motion under gravity

Answers

Answered by agamaujla12121212369
0
v=0, a = -32ft/s^2, s= 9ft

v^2-u^2=2as

0-u^2=2x-32x9

therefore u = 24ft/s

v=u+at

0=24-32xt, therefore t = 3/4 sec

so the ball returns to the juggler after 3/4 sec

To maintain proper distance, the balls must be thrown at an interval of 3/5/2=3/8sec

Therefore the distance between the balls is

s = ut+[1/2]at^2

s = 24x[3/8] - [1/2]x32x[9/64] = 6.75ft

Hence d is the correct option
Similar questions