Class 11
Linear inequations
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Answered by
6
HELLO THERE!
Here's your answer:
(i) 9x - 25 ≤ 7 + 3x
=> 9x - 3x ≤ 7 + 25
=> 6x ≤ 32
=> x ≤ 5.3
Now, since x ∈ I, only integers can be taken.
So, solution set is:
x = {......-3, -2, -1, 0, 1, 2, 3, 4, 5}, x ∈ I
(ii) 4(x + 5) > -10
=> 4x + 20 > -10
=> 4x > -30
=> x > -7.5
So, the solution set is:
x = {-7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4...........}, x ∈ I
Here's your answer:
(i) 9x - 25 ≤ 7 + 3x
=> 9x - 3x ≤ 7 + 25
=> 6x ≤ 32
=> x ≤ 5.3
Now, since x ∈ I, only integers can be taken.
So, solution set is:
x = {......-3, -2, -1, 0, 1, 2, 3, 4, 5}, x ∈ I
(ii) 4(x + 5) > -10
=> 4x + 20 > -10
=> 4x > -30
=> x > -7.5
So, the solution set is:
x = {-7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4...........}, x ∈ I
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Ayushasutkar1:
How does x € I, means x belongs to integer?
Both are valid.
Answered by
4
Hi ,
x € I
i ) 9x - 25 ≤ 7 + 3x
9x - 3x ≤ 7 + 25
6x ≤ 32
x ≤ 32/6
x ≤ 5.33...
<-------------------------|------|------|-------•--------->
<------------------------------------4-------5
ii ) 4( x + 5 ) > -10
4x + 20 > - 10
4x > - 10 - 20
4x > - 30
x > -30/4
x > - 7.5
< |•-----------|-----|-----|-------------->
- 7------------>
I hope this helps you.
: )
x € I
i ) 9x - 25 ≤ 7 + 3x
9x - 3x ≤ 7 + 25
6x ≤ 32
x ≤ 32/6
x ≤ 5.33...
<-------------------------|------|------|-------•--------->
<------------------------------------4-------5
ii ) 4( x + 5 ) > -10
4x + 20 > - 10
4x > - 10 - 20
4x > - 30
x > -30/4
x > - 7.5
< |•-----------|-----|-----|-------------->
- 7------------>
I hope this helps you.
: )
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