Question

class 11 mathematics, plz help me, it's urgent...​

Answer 1

Answer:

0

Step-by-step explanation:

Although I am in class 10 I can help ..

$\lim_{h \to 0} \frac{xsinx(cosh-1)}{h}\\\\ \implies \lim_{h \to 0} xsinx\times \frac{(cosh-1)}{h}$

$\implies \lim_{h \to 0} xsinx\times \frac{(-2sin^2(h/2))}{h}\\\\ \implies \lim_{h \to 0} xsinx\times \frac{-sin^2(h/2)}{h/2}\\\\\implies \lim_{h \to 0} xsinx\times0\\\\\implies 0$

Answer 2

QUESTION

tan 480 = tan (360+120) = tan 120. here as the tan will fall in 2nd quadrant it will be negative. therefore tan120 = tan(180-60) = -tan 60 -√3.