Math, asked by riddschauhan06, 2 days ago

class 11 maths matsh maths maths.​

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Answers

Answered by bhagmatichoudhary966
1

Answer:

y=

x

2

+2x−7

x

2

+34x−71

yx

2

+2xy−7y=x

2

+34x−71

x

2

(1−y)+2x(17−y)+7y−71=0x∈R

4(17−y)

2

−4(1−y)(7y−71)≥0

4(17

2

+y

2

−34y)−4(−7y

2

−71+78y)≥0

⇒8y

2

−112y+360≥0

⇒y

2

−14y+45≥0

⇒(y−9)(y−5)≥0

y∈(−∞,5)∪(9,∞)

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