Question

Class 11 Physics

A particle moves in a circle of radius 2cm at a given speed given by v=4t, where v is in cm/s and t is in seconds.
a) find the tangential acceleration at t=1s.
b) Find the total acceleration at t=1s.

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Answer 1

$\huge\star{\mathfrak{\underline{\underline{\red{Answer}}}}}\star$

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a) $\bold{\tt{\blue{Tangential\:Acceleration}}}$

Tangential Acceleration= $\frac{dv}{dt}$

v=4t

$\implies$$\frac{d}{dt}$(4t)

Here,

At t= 1 sec

Therefore,

Tangential Acceleration=4cm/s²

b) $\bold{\tt{\blue{Total \:Acceleration=}}}$ $\bold \sqrt{{(centripetal \:Acceleration)}^{2} + {(Tangential\: Acceleration)}^{2}}$

Centripetal Acceleration=$\large\frac{{v}^{2}}{R}$

$\implies$$\large\frac{{4}^{2}}{2}$

$\implies$8cm/s²

Centripetal Acceleration=8cm/s²

Now,

Total Acceleration= $\sqrt{{4}^{2}{8}^{2}}$

$\star$$\star$ Total Acceleration=4√5 cm/s²$\star$$\star$

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Answer 2

Answer:

Here is your answer ll

Hope it helps you