Question

*Class 11th question*»
Determine the empirical formula of an oxide of iron which has 69.9% iron
30.1% dioxygen by mass. Don't Copy from anywhere, otherwise I will report your answer​

Answer 1

Answer:

According to your Question, iron oxide has 69.9% iron and 30.1% dioxygen by mass, 100 g of iron oxide contains 69.9 g iron and 30.1 g dioxygen, number of moles of iron present in 100 g of iron oxide are 55. 869.

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Answer 2

Explanation:

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Iron=69.9/ 55.8

=1.25

Dioxygen =30.1/31.9

=0.94

≈1

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@ Twilight Astro ✌️☺️