Physics, asked by MagicalLove, 1 month ago

Class - 12 , physics

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Answers

Answered by Anonymous
18

\huge \fbox \blue{Answer✪}

y =  \sinωt +  \cosωt =  \sqrt{2}  \left(  \frac{1}{ \sqrt{2}  }  \sinωt +  \frac{1}{ \sqrt{2} }  \cosωt \right) \]

 =  \sqrt{2} ( \sin \:   \cos\pi/4 \div  \cosωt  \: \sin\pi/4)

 =  \sqrt{2}  \sin(ωt + \pi/4)

[\text{like \: y =  Asin(ωt +∅) }  ]

\text{So, amplitude   is }  \sqrt{2} \text{ \: units  }

\text{Initìal Displacement at  \: t = 0 \: is}

 \\  \\  \\  \\ \sf \colorbox{lightgreen} {\red★ANSWER ᵇʸɴᴀᴡᴀʙﷻ}

Answered by sanju2363
8

Explanation:

\huge \fbox \blue{Answer✪}

 \\  \\  \\

</p><p>= \sqrt{2} ( \sin \: \cos\pi/4 \div \cosωt \: \sin\pi/4)</p><p>

= \sqrt{2} \sin(ωt + \pi/4)

[\text{like \: y = Asin(ωt +∅) } ]

\text{So, amplitude is } \sqrt{2} \text{ \: units }

\text{Initìal Displacement at \: t = 0 \: is}

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