class 12 physics electrostatic ....plz answer frndzz if you know
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HELLO !!
POINTS TO NOTICE:-
- IN QUESTIONS RELATED TO COLUMBS LAW AND AND DISTANCE
- FIRST TAKE RELATION RELATED TO NEWTON 3RD LAW i.e F1 = -F2
- NOW MAKE OUT A RELATION BETWEEN F1 AND F2
- IF DISTANCE COORDINATES ARE GIVEN THEN ALWAYS SHOW AS VECTOR CAPS
- SOLVE FOR Q OR NEEDED TERM
GIVEN:-
- QI = 5 × 10^6 C
- Q2 = 3 × 10 ^6 C
- COORDINATES ( 3,5,1 ) , (1,3,2)
TO FIND :- F12 AND F21 and magnitude
METHOD USED :-
COLUMBS LAW OF VECTOR FORM
SOLUTION:-
SEE ,
F12 ●----------------------------------------------● F21
Q1 = 5 × 10⁶ Q2 = 3 × 10⁶
( 3,5,1 ) (1,3,2)
CONSIDERING CHARGES TO BE REPULSIVE
HENCE , WE CAN SAY F12 = - F21
NOW BY COLUMBS LAW AND EQUATING ,
first of all,
THE DISTANCE COORDINATES ARE WRITTEN AS R1 = 3i^ + 5j^ + k^
R2 = I^ + 3J^ + 2Ķ^
DISTANCE BETWEEN POINTS BY DISTANCE FORMULA ARE :-
R12^ = R12 = 2I^ + 2J^ - K^ ( R2 - R1 = 2I^ + 2J^ - K^)
|R12| 3
F12 = K|Q1×Q2| × R12 = -F21
(R12)²
PUTTING THE VALUE AND SOLVING WE GET
F12 = 5 × 10^-3 (2i^ + 2j^ - k^) N
|FI2| = 1.5 × 10 ^-3N
F12 = - F21 = 5 × 10^-3 (2i^ + 2j^ - k^) N
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