Physics, asked by rashmibhardwaj1518, 10 months ago

class 12 physics electrostatic ....plz answer frndzz if you know ​

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Answered by Anonymous
1

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Answered by lakshyabhardwaj20031
1

HELLO !!

POINTS TO NOTICE:-

  1. IN QUESTIONS RELATED TO COLUMBS LAW AND AND DISTANCE
  2. FIRST TAKE RELATION RELATED TO NEWTON 3RD LAW i.e F1 = -F2
  3. NOW MAKE OUT A RELATION BETWEEN F1 AND F2
  4. IF DISTANCE COORDINATES ARE GIVEN THEN ALWAYS SHOW AS VECTOR CAPS
  5. SOLVE FOR Q OR NEEDED TERM

GIVEN:-

  1. QI = 5 × 10^6 C
  2. Q2 = 3 × 10 ^6 C
  3. COORDINATES ( 3,5,1 ) , (1,3,2)

TO FIND :- F12 AND F21 and magnitude

METHOD USED :-

COLUMBS LAW OF VECTOR FORM

SOLUTION:-

SEE ,

F12 ---------------------------------------------- F21

Q1 = 5 × 10 Q2 = 3 × 10

( 3,5,1 ) (1,3,2)

CONSIDERING CHARGES TO BE REPULSIVE

HENCE , WE CAN SAY F12 = - F21

NOW BY COLUMBS LAW AND EQUATING ,

first of all,

THE DISTANCE COORDINATES ARE WRITTEN AS R1 = 3i^ + 5j^ + k^

R2 = I^ + 3J^ + ^

DISTANCE BETWEEN POINTS BY DISTANCE FORMULA ARE :-

 \sqrt{( {3 - 1})^{2} }  + \sqrt{( {5 - 3})^{2} }  +  \sqrt{( {1 - 2})^{2} }

 \sqrt{ {2}^{2} }  +  \sqrt{ {2}^{2} }  +   \sqrt{ { - 1}^{2} }

 \sqrt{9}

 = 3m

R12^ = R12 = 2I^ + 2J^ - K^ ( R2 - R1 = 2I^ + 2J^ - K^)

|R12| 3

F12 = K|Q1×Q2| × R12 = -F21

(R12)²

PUTTING THE VALUE AND SOLVING WE GET

F12 = 5 × 10^-3 (2i^ + 2j^ - k^) N

 |f12|  =  (\sqrt{ {2}^{2} }  +    \sqrt{ {2}^{2} }  +  \sqrt{ { - 1}^{2} }  ) \times 5 × 10 {}^{ - 3}

|FI2| = 1.5 × 10 ^-3N

F12 = - F21 = 5 × 10^-3 (2i^ + 2j^ - k^) N

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