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Question :
What is the magnitude force per unit lengh on a wire carrying a current of 8A and making an angle of 30° with the direction of a uniform magnetic field of 0.15 T ?
AnSwer :
Current in the wire, I = 8A.
Magnitude of the uniform magnetic field, B = 0.15T
Angle between the wire and magnetic field,θ = 30°
Magnetic froce per unit lengh on the wire is given as :-
➠ f = BIsinθ
➠ f = 0.15 × 8 × 1 × sin30°
➠ f = 0.15 × 8 × 1/2
➠ f = 0.15 × 4
➠ f = 0.6 Nm
Thus, the magnetic froce per unit Length on the wire is 0.6 Nm
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