Question

Class 12th

Physics

Chapter :- Atoms

The first line of Lyman series in a hydrogen spectrum has a wavelength of 1210 Angstrom. The corresponding line of hydrogen like atom of Z = 11 is equal to :-

a. 4000 A

b. 100 A

c. 40 A

d. 10 A​

Answer 1

Answer:

The wavelength of first line of the Lyman series for hydrogen is 1210

The first line of the lyman series in a hydrogen spectrum has a wavelength of 1210 Å. The corresponding line of a hydrogen like atom of Z=11 is equal to.

D,is the answer.

Explanation:

hope it helps you.

mark me as brainliest

Answer 2

Option d). 10 Angstrom is the correct option.

Explanation :

Wavelength, Lambda = 1210 Angstrom ( given)

For Lyman series, n1 = 1 & n2 = 2 [ Lyman <Balmer < Paschen < Brackett < Pfund ]

This is for H - atom ( Z = 1) . Use Rydberg formula to get the resultant value in terms of R.

Now, again put the Z = 11, in resultant expression to get the wavelength of H - like atom ( Z = 11, Na ) .