Math, asked by Arneshjha, 5 months ago

CLASS-5

TH

NAME- ----------------------

SUBJECT-MATHS ROLL NO. --------------------

MONTH-DECEMBER PARENTS SIGNATURE- --------------

(FORMING NUMBER)

Q1. Write the decimal number:

(a) 400 + 60 + 2 + 9/10+ 5/100 =

(b) 20 + 4 + 3/100 + 8/1000 =

Q2. Write the following as decimals:

(a) Two tenths =

(b) Four decimal three two one

Q3. Draw atleast one shape which can fold into a cube .

Q4. Match the following:

(a) Rupee ½ 25 paise Rupee 0.99

(b) Rupee1/4 75 paise Rupee 0.50

(c) Rupee 99/100 50 paise Rupee 0.75

(d) Rupee ¾ 99 paise Rupee 0.25

(BASIC UNDERSTANDING)

Q5. Fill in the blanks:

(a) ---------------- is the region enclosed between the boundaries of a figure.

(b) Area of a rectangle = ----------------

(c) Area of a square = ---------------

(d) volume of a cuboid = --------------

(e) The sum total of the lengths of all the line segments of a simple closed figure is called its ----------------------

(f) Area of a triangle = ½ Base X-------------Q6. Circle the correct one:

( a) 300.4 ÷ 2 = 1502 15.02 1.502 150.2

(b) 94.95 ÷ 45 = 0.211 2.11 21.1 211

(c) The area of a square of side 16 cm will be

(i) 32 sq cm (ii) 356 sq cm (iii) 256 sqcm.​

Answers

Answered by aryan9960
4

Step-by-step explanation:

F = (m1 * V1 - m0 * V0) / (t1 - t0)

Newton's second law talks about changes in momentum (m * V) so, at this point, we can't separate out how much the mass changed and how much the velocity changed. We only know how much product (m * V) changed.

Let us assume that the mass stays a constant value equal to m. This assumption is pretty good for an airplane, the only change in mass would be for the fuel burned between point "1" and point "0". The weight of the fuel is probably small relative to the weight of the rest of the airplane, especially if we only look at small changes in time.. If we were discussing the flight of a baseball, then certainly the mass remains a constant. But if we were discussing the flight of a bottle rocket, then the mass does not remain a constant and we can only look at changes in momentum. For a constant mass m, Newton's second law looks like:

F = m * (V1 - V0) / (t1 - t0)

The change in velocity divided by the change in time is the definition of the acceleration a. The second law then reduces to the more familiar product of a mass and an acceleration:

F = m * a

Answered by vineethajuttiga
20

Answer:

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