Question

class-7
ch-7
congruence of triangle


In the given quadrilateral ABCD show that <A=< C



Help me...​

Answer 1

${\huge{\purple{\underline{\boxed{\bf{\pink{\mathfrak{Your\:}{\huge{\orange{\underline{\boxed{\bf{\green{\mathfrak{\:Answer}}}}}}}}}}}}}}}$

Given :-

• AB = CD
• ∠ABD = ∠CDB

In triangles ABD and CDB,

• AB = CD (Given)
• ∠ABD = ∠CDB (Given)
• BD = BD (Common)

Thus, by SAS congruence rule,

• Triangle ABD ≅ Triangle CDB

So, By CPCT,

• ∠A = ∠C

Hence, Proved.✅️

_________________________________________